Category: Blog

Home  ›  Blog  ›  Page 17

AQ: High AC current inductors

There are several issues at work here. For high AC current inductors, you want to have low core losses, low proximity loss in the windings, and low fringing effects.

At normal frequencies, ferrites are by far the lowest core loss, much better than MPP and other so called “low-loss” materials. So you would like to use them from this aspect.

A toroid gives the greatest winding surface for the magnetic material, letting you use the least number of layers and hence minimizing proximity loss. The toroid also has the advantage of putting all the windings on the outside of the structure, facilitating cooling. This is very important.

However, you can’t easily gap a toroid of ferrite, it’s very expensive.

Some aerospace applications actually cut the ferrite toroid into segments and reassemble them with several gaps to solve the problem. The multiple gaps keep fringing effects low. It might be nice if you could buy a set of toroidal segments so you don’t have to do the cutting because that is a big part of the cost. I don’t know if that is a reasonable thing to do, maybe someone can comment.

Once you go to MPP, the core loss goes up, but the distributed gap minimizes the fringing losses.

The MPP lets you run somewhat higher on current before saturation, but if you have high ac you can’t take full advantage of that due to the core losses.

All these tradeoffs (and quite a few more not mentioned for brevity) are the reason that so many different solutions exist.

AQ: Moving data around within memory of an individual PLC

The first question would have to be – why do want to do it? If the data already exists in one location that is accessible by all parts of the program, why are you going to use up more PLC memory with exactly the same data?

Well, there are a couple of candidate reasons. One might be recipe data. You have an area of memory with a set of stored recipes for different products, and at an appropriate moment you want to copy a specific recipe from the storage area to the working area. The first thing to be said about that is that if your recipes are at all complex and you have a requirement to have a significant number of different recipes, then PLC memory is probably not the right place to be storing them. The ultimate, these days, of course, is that recipes are created by techies on PCs away from the production area, in nice quite, comfortable labs or whatever, and are stored on a SQL server. Only the recipe for today’s actual production run gets transferred to the PLC. But there are some applications where there is a limited number of different recipes required and the recipes themselves are quite simple, when it can be reasonable to store the recipes in PLC memory.

A second reason for copying memory areas within the same PLC is for procedures, sub-routines or whatever. But again, these days, all PLC languages have some sort of in-built facility for procedures – what Rockwell uniquely call Add On Instructions, what everyone else calls UDFBs – user defined function blocks. In any case, the point is that these facilities usually make all that memory management stuff transparent to the programmer. You just configure the UDFB and call it as required. The compiler takes care of all the memory data moves for you.

Another reason for copying memory, actually related to the previous, is a technique much used by PLC programmers where they use an area of memory as a ‘scratch-pad’. So they will copy some unprocessed data to the scratchpad area, all of the operations performed on the data take place using the scratchpad, and at the end, they copy the processed data back again. Again, it is questionable how much this technique is actually required these days, I would suggest that it most cases, there probably is a better way using a UDFB. But I have seen some programmers who routinely include a scratchpad area within any UDFBs they define.

AQ: Creepage in thermal substations

The term creepage distance is specifically associated with porcelain insulators used in the Air Insulated substations. Insulator surface attracts dust, pollution (in industrial areas) and salt (along the sea coast) and these form a conducting layer on the surface of the insulator body when the surface is wet. As long as this surface is dry, there is not much problem. But when it becomes wet during early morning or during winter season the outer surface forms a conducting path along the surface from high voltage terminal to earthed metal fitting at the end of metallic structure and may lead to surface conduction and finally external flash-over. The insulators are provided with Sheds to limit the direct exposer to mist or dew. The protected area of the sheds will not allow formation of continuous conducting layer along the surface of insulator as the part of surface which is under the sheds may not become wet due to mist or dew and this part (length along the bottom surface) of the insulator surface is called protected creepage.

Measurement of corona inception and extinction voltages give a fair idea about the possible flashover even with protected creepage. But these will change under different levels of pollution.
This problem is not present with Composite insulators as the Silicone rubber sheds surface does not allow formation of continuous wet conducting layer as the surface of these insulators is Hydrophobic. Hence higher creepage is not considered for composite insulators.

However air density is also a limiting factor for deciding the creepage of insulators, necessitating higher creepage in case of higher altitudes.
You may have to assess the level of pollution and altitude of substation and select the creepage accordingly.
Medium pollution levels may be 25mm/kV
Very high pollution areas like on the sea coast and chemical and pharmaceutical industrial areas 31mm/kV where the insulators may become expensive alternatively periodic hot line washing is also another solution for cleaning of pollution on insulators.
In case of very high pollution levels GIS may be safe solution (if cost is not an issue)

Thermal substations where there are no electrostatic precipitators may also experience equipment failures due to pollution. Pressurized equipments like SF6 gas circuit breaker experienced external flash-overs during winter months in Northern India The utility was not accepting the theory of insulation failure due to pollution initially but they had to accept the cause of failure as pollution when they had similar failure in the consecutive year during the same winter months and they have resorted to hot line washing since then and there are no more such failures. Sometimes these deposits may not be seen glaringly but failure may happen.

AQ: Sub-transmission network

Q:
What factors determine current distribution between two 33kV feeders feeding a 33/11kV Substation within a sub-transmission network.

A:
Try the voltage divider rule. Take the R + X of each feeder (resistance and reactance) and find the Z. Remember that square root of R² + X² = Z. Now that you have the Z of each feeder, now find the Z of the two in parallel. To do this we have Z = 1/(1/Z1 +1/Z2). So, if Z1 = 2.16 ohms and Z2 = 1.67 ohms, then our Z of the two in parallel is 0.94 ohms. Now we pass the current of the entire substation between these two feeders. Let’s say that the current is 240 amps. Now we have 240Ax0.94ohms = 226 volts (IxZ=V). And since voltage divided by impedance gives us current (V/Z = I) we now take the voltage drop across the two feeders in parallel and divide each of the feeder impedances to get the separate feeder current. So we get 226V/2.16ohms = 105 amps (feeder 1) and 226V/1.67ohms = 135 amps (feeder 2). I have not tried this with your exact situation. Having different voltages from two different substations will change things, but at least this way you have a good start on the problem.

Since one end is tied together and the two other ends are from different substations, then you will have the classic voltage sending and receiving formula. Since the load is the one substation, then their will only be one power factor of the one load, so I would think this formula would apply: Es = Square Root of ((ErCosƟ + IR)² +(ErSinƟ +IX)²), which is square root of ((Receiving voltage times the cosine of the current phase angle plus current times resistance of the line)² + (Receiving voltage times Sine of the current phase angle plus current times reactance of the line)²). The voltage drop across each line would be VD=I(RcosƟ +XsinƟ) where R is the line resistance and X is the line reactance and the Ɵ is the phase angle of the load.

AQ: Automation solution

Automation is a solution:
1. To reduce the manpower & the CTC due to them.

2. Few skilled technicians can run the automated machines smoothly, with much lesser number of errors & faults (as human is not directly controlling every thing & is not burdened with multitasking challenge for extended duration which causes fatigue and hence errors/faults)

3. The power consumption & time to market can be estimated & reduced as machines will be operated on time & can work for longer durations than human beings & they don’t ask for tea/coffee/lunch breaks nor they ask for incentives. (Care for peoples who are maintaining them as well as care for machines which are earning profits for you, by regular maintenance & regular proper inspection of their conditions). Now days very good automatic power mgmt processors/controllers are available which can maintain the power as per the defined conditions as per the load & real time necessity.

4. Train the operators / technicians regularly to keep them up to date with tricks / methods / operations / principals to handle most situations by their own (will reduce the cost of a nonsense manager who is kept to yell, threat & discriminate subordinates and know only one slogan: “do it properly, otherwise, i will ….”). A training department which actually hold the capability to technically train employees from labor to talented engineers is a necessity of this age, as things are not remains just a lifting boulder & digging holes. We are living in an advance age in which we are having many expectations, competition & external pressures.

5. Finance bugs cries for expenses on NRE costs, salaries & treats this investments like invested in a share/equity/debt fund, but, earning from a business & financial mgmt capability must be inline with level & operations performed by the company. Instead of keeping low minds in tech industries, hire the engineers who has reached to an expertise level in automation industry & know the in depth issues occurring in between & underneath to estimate & expect correct values & timelines. Qualified project managers are much more realistic in their approaches, thoughts, assumptions & mentality.

AQ: System with difference neutral

Q:
I have one system with two source. One from genset and the other from PLN (national power supply company) that each system has neutral.
The question is
1. Is there any problem if I connect both neutral directly?
2. Is there any spark when I connect both neutral?
3. How is the best solution to connect both neutral?

A:
1. I understand that the Genset is dedicated for essential load as an Emergency power supply which will be operated by hand (only in Manual Mode).

2. The Control Philosophy for a Generator that intended to be connected to PLN as emergency power source depends on the local service provider regulations.

3. Usually in your case there should be Electrical as well as Mechanical interlocks between the mains incomer & genset main breaker. ie both Sources will never be in Synchronism ( will not feeding the same load simultaneously).This measures will ensure that there will be only neutral point to the system.

AQ: Cross regulation for multiple outputs

Cross regulation is a very important component of multiple outputs. This can be done in several ways: transformer coupling, mutually coupled output filter chokes (forward-mode) and/or shared output sensing voltages/currents. All, of which, are impossible to model. I have tried them all.

I have sort of written of the first two off, since it is under the control of external vendors, which make their own decisions as to their most cost effective solutions. At best, transformer solutions yield a +/- 5 percent regulation, and can be many times much worse. .Coupled inductors yield a much better cross regulation, but the turns ratio is critically important. If you are off by one turn, you loose a percentage of efficiency.

Shared current/voltage cross sensing is so much more common sense. First, choose the respective weighing of the percentage of sense currents from each outputs approximately in proportion to their respective output powers. Keep in mind that, without cross-sensing, the unsensed outputs can be as much +/- 12 % out of regulation. Decide your sense current through you lower sense resistor. Then multiply your percentages by this sense current from your positive outputs. Calculate each output’s resistance to provide that respective current. Try it, you will be amazed. The negative outputs will also improve immensely.

One can visualize this by, if one senses only one output, only the load of that output influences the feedback loop, which, for example, increases the pulsewidth for each increase in load of the heavily loaded output. The lighter, unsensed loads go crazy. By cross sensing, the lighter loads are more under control and the percent of regulation of the primary load is loosened somewhat.
By sharing the current through the lower sense resistor, you can improve the regulation of every output voltage in a multiple output power supply.

AQ: Soft start motor tripped in fuel oil suction and discharge

First of all check all the component i.e.CB, CT, Heat Element, and the O/L setting then megger the motor to be shore that there is no problem with the motor winding insulation.
After that let the mechanical check the vibration analyses during the start-up also measure the startup currant of the motor and diffidently you will find where is the problem.
It could be a relay setting; or problem in the insulation; or even a problem in the motor itself.

On the other hand, check the motor on No Load condition and tune it to the Soft starter before coupling it to the pump.
Auto Tuning feature is generally inbuilt to Advanced soft starters.
If the No load startup of the motor is perfect, 2 causes arise:
1) Improper design.
2) Viscosity _ this can be tackled if you can make some temporary arrangement for pre-heating to confirm if this is the culprit.

As using soft starter could result in reducing torque of the motor. Soft starter normally reduces starting current by reducing starting voltage. However, decreasing voltage will lead to starting toque reduction. Hence, the motor may take longer time, especially when driving high-inertia load, with somewhat high current until it reach its full speed. Using an inverter will help you get full starting torque or even boost up it to 150-200% while keeping starting current at 150-200% of full load. Installation of heat tracing might also help and economic.

Assuming it is an electrical problem. On a motor of this size it has separate overload protection from the ground fault and short circuit protection. There are tolerance levels for motor that you may not be within. However a megger will not answer all the possibilities with motors unless you are ready to perform polarization index test etc….A power analyzer will allow you to see the operation in real world application. Assuming you have confirmed this is an electrical problem your next step would be to use a power analyser. You should be able to confirm by the signature and different placements of the analyzer the problem. Analyzer should be around all three phases.

AQ: How to design an Panel required for PLC / MCC / Drive

1. The regular industrial standard size panel available with most of the panel fabricator’s.
2. Type of protection (used to say as IP).
3. Spacing depends upon the Power handled by the conductors inside Panel and the ventilation system.
4. Cable Entry / Bus bar entry may depend on the application and site condition. it may be at rear/bottom or at the top.
5. When comes to Drive, if the site condition is too hot then an industrial ac is required usually attached at the side of the panel.
6. Drive to drive required spacing (Check the manual of the drive}, since the power switching activity take place inside the drive.
7. Provide required space for the transformers and AC-choke since they create magnetic flux in ac circuits.
8. Don’t mix the Control cable, Power cable, Signal cable and Communication cable together in the cable tray… Otherwise you will be wired…
9. Keep the control on mcb/mccb/mpcb in handy location. So that its easier for operator to control it frequently and not disturbing other circuits..
10. Plc will be acquiring the top position in the panel since there is nothing to do with it once installed. Just we will be monitoring the status.
11. Don’t place the Plc nearby to the incoming or outgoing heavy power terminals..
12. Mcc panel are easy thing to do, but do the exact calculation for the ACB selection in the incomer side. Since each feeder will be designed with tolerance level.

There being a lot more than 12 guidelines to follow. What
about back-up power for the PLC? What about internal heat flow considerations
(not just does it need an AC or not)? How much space between terminal blocks
and wireway? What about separate AC and instrument grounds? What about wireway
fill? What about wire labels? What about TSP shields? What about surge
protection? In my experience, there are plenty of people that can design a
panel but if they haven’t gone to the field with it then they haven’t been able
to learn from their design mistakes.

The best thing you can do is start your design but you
really need to be guided by an experienced designer.

AQ: Right Half Plane Pole

Very few know about the Right Half Plane Pole (not a RHP-Zero) at high duty cycle in a DCM buck with current mode control. Maybe because it is not really a problem.
It is said that this instability starts above 2/3 duty cycle – I think that must be with a resistive load. If loaded with a pure current source, it starts above 50% duty cycle.

Here is a little down-to-earth explanation:
If you run a buck converter at high duty cycle but DCM, it probably works fine and is completely stable. Then imagine you suddenly open the feedback loop, leaving the peak current constant and unchanged. The duty cycle will then rush either back to 50% or to 100% if possible. You now have a system with a negative output resistance – if Voltage goes up, the output current will increase.

You can see it by drawing some triangles on a piece of paper: A steady state DCM current triangle with an up-slope longer than the down-slope and a fixed peak value. Now, if you imagine that the output voltage rises, you can draw a new triangle with the same peak current. The up-slope will be longer, the down-slope will be shorter but the sum of times will be longer than in the steady state case. The new triangle therefore has a larger area than the steady state triangle, which means a higher average output current. So higher output voltage generates higher output current if peak current is constant. Loaded with a current source, it is clear that this is an unstable system, like a flipflop, and it starts becoming unstable above 50% duty cycle.

However, when you close the feedback loop, the system is (conditionally) stable and the loop gain is normally so high at the RHP Pole frequency that it requires a huge gain reduction to make it unstable.

It’s like when you drive on your bike. A bike has two wheels and therefore can tilt to either side – it is a system with a low frequency RHPP like a flipflop. If you stand still, it will certainly tilt to the left or to the right because you have no way to adjust your balance back. But if you drive, you have a system with feedback where you can immediately correct imbalance by turning the handlebars. As we know, this system is stable unless you have drunk a lot of beers.